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Formulas double angle serve to express sines, cosines, tangents, cotangents of an angle with a value of 2 α, using trigonometric functions of the angle α. This article will introduce all double angle formulas with proofs. Examples of application of formulas will be considered. In the final part, the formulas for triple and quadruple angles will be shown.

Yandex.RTB R-A-339285-1

List of double angle formulas

To convert double angle formulas, remember that angles in trigonometry have the form n α notation, where n is natural number, the value of the expression is written without parentheses. Thus, the notation sin n α is considered to have the same meaning as sin (n α) . When denoting sin n α, we have a similar notation (sin α) n. The use of the recording is applicable to everyone trigonometric functions with powers n.

Below are the double angle formulas:

sin 2 α = 2 · sin α · cos α cos 2 α = cos 2 α - sin 2 α , cos 2 α = 1 - 2 · sin 2 α , cos 2 α = 2 · cos 2 α - 1 t g 2 α = 2 t g α 1 - t g 2 α c t g 2 α - c t g 2 α - 1 2 c t g α

Note that these formulas sin and cos are applicable with any value of the angle α. The double angle tangent formula is valid for any value of α, where t g 2 α makes sense, that is, α ≠ π 4 + π 2 · z, z is any integer. The double angle cotangent exists for any α, where c t g 2 α is defined at α ≠ π 2 z.

The cosine of a double angle has the triple notation of a double angle. All of them are applicable.

Proof of double angle formulas

The proof of the formulas starts from the addition formulas. Let's apply the formulas for the sine of the sum:

sin (α + β) = sin α · cos β + cos α · sin β and the cosine of the sum cos (α + β) = cos α · cos β - sin α · sin β. Let's assume that β = α, then we get that

sin (α + α) = sin α · cos α + cos α · sin α = 2 · sin α · cos α and cos (α + α) = cos α · cos α - sin α · sin α = cos 2 α - sin 2 α

Thus, the formulas for the sine and cosine of the double angle sin 2 α = 2 · sin α · cos α and cos 2 α = cos 2 α - sin 2 α are proven.

The remaining formulas cos 2 α = 1 - 2 sin 2 α and cos 2 α = 2 cos 2 α - 1 lead to mind cos 2 α = cos 2 α = cos 2 α - sin 2 α, when replacing 1 with the sum of squares according to the main identity sin 2 α + cos 2 α = 1 . We get that sin 2 α + cos 2 α = 1. So 1 - 2 sin 2 α = sin 2 α + cos 2 α - 2 sin 2 α = cos 2 α - sin 2 α and 2 cos 2 α - 1 = 2 cos 2 α - (sin 2 α + cos 2 α) = cos 2 α - sin 2 α.

To prove the formulas for the double angle of tangent and cotangent, we apply the equalities t g 2 α = sin 2 α cos 2 α and c t g 2 α = cos 2 α sin 2 α. After the transformation, we obtain that t g 2 α = sin 2 α cos 2 α = 2 · sin α · cos α cos 2 α - sin 2 α and c t g 2 α = cos 2 α sin 2 α = cos 2 α - sin 2 α 2 · sin α · cos α . Divide the expression by cos 2 α, where cos 2 α ≠ 0 with any value of α when t g α is defined. We divide another expression by sin 2 α, where sin 2 α ≠ 0 with any values of α, when c t g 2 α makes sense. To prove the double angle formula for tangent and cotangent, we substitute and get:

– there will certainly be tasks on trigonometry. Trigonometry is often disliked for the need to cram a huge number of difficult formulas, teeming with sines, cosines, tangents and cotangents. The site already once gave advice on how to remember a forgotten formula, using the example of the Euler and Peel formulas.

And in this article we will try to show that it is enough to firmly know only five simplest trigonometric formulas, and about the rest have general idea and bring them out as you go. It’s like with DNA: the molecule does not store the complete blueprints of a finished living being. Rather, it contains instructions for assembling it from available amino acids. So in trigonometry, knowing some general principles, we will get everything necessary formulas from small set those that must be kept in mind.

We will rely on following formulas:

From the formulas for sine and cosine sums, knowing about the parity of the cosine function and the oddness of the sine function, substituting -b instead of b, we obtain formulas for differences:

Sine of the difference: sin(a-b) = sinacos(-b)+cosasin(-b) = sinacosb-cosasinb
Cosine of the difference: cos(a-b) = cosacos(-b)-sinasin(-b) = cosacosb+sinasinb

Putting a = b into the same formulas, we obtain the formulas for sine and cosine of double angles:

Sine of double angle: sin2a = sin(a+a) = sinacosa+cosasina = 2sinacosa
Cosine of double angle: cos2a = cos(a+a) = cosacosa-sinasina = cos2 a-sin2 a

The formulas for other multiple angles are obtained similarly:

Sine of a triple angle: sin3a = sin(2a+a) = sin2acosa+cos2asina = (2sinacosa)cosa+(cos2 a-sin2 a)sina = 2sinacos2 a+sinacos2 a-sin 3 a = 3 sinacos2 a-sin 3 a = 3 sina(1-sin2 a)-sin 3 a = 3 sina-4sin 3a
Cosine of triple angle: cos3a = cos(2a+a) = cos2acosa-sin2asina = (cos2 a-sin2 a)cosa-(2sinacosa)sina = cos 3 a- sin2 acosa-2sin2 acosa = cos 3 a-3 sin2 acosa = cos 3 a-3(1- cos2 a)cosa = 4cos 3 a-3 cosa

Before we move on, let's look at one problem.
Given: the angle is acute.
Find its cosine if
Solution given by one student:
Because , That sina= 3,a cosa = 4.
(From math humor)

So, the definition of tangent relates this function to both sine and cosine. But you can get a formula that relates the tangent only to the cosine. To derive it, let’s take the main trigonometric identity: sin 2 a+cos 2 a= 1 and divide it by cos 2 a. We get:

So the solution to this problem would be:

(Since the angle is acute, when extracting the root, the + sign is taken)

The formula for the tangent of a sum is another one that is difficult to remember. Let's output it like this:

Immediately displayed and

From the cosine formula for a double angle, you can obtain the sine and cosine formulas for half angles. To do this, to the left side of the double angle cosine formula:
cos2 a = cos 2 a-sin 2 a
we add one, and to the right - a trigonometric unit, i.e. the sum of the squares of sine and cosine.
cos2a+1 = cos2 a-sin2 a+cos2 a+sin2 a
2cos 2 a = cos2 a+1
Expressing cosa through cos2 a and performing a change of variables, we get:

The sign is taken depending on the quadrant.

Similarly, subtracting one from the left side of the equality and the sum of the squares of the sine and cosine from the right, we get:
cos2a-1 = cos2 a-sin2 a-cos2 a-sin2 a
2sin 2 a = 1-cos2 a

And finally, to convert the sum of trigonometric functions into a product, we use the following technique. Let's say we need to represent the sum of sines as a product sina+sinb. Let's introduce variables x and y such that a = x+y, b+x-y. Then
sina+sinb = sin(x+y)+ sin(x-y) = sin x cos y+ cos x sin y+ sin x cos y- cos x sin y=2 sin x cos y. Let us now express x and y in terms of a and b.

Since a = x+y, b = x-y, then . That's why

You can withdraw immediately

Formula for partitioning products of sine and cosine V amount: sinacosb = 0.5(sin(a+b)+sin(a-b))

We recommend that you practice and derive formulas on your own for converting the difference of sines and the sum and difference of cosines into the product, as well as for dividing the products of sines and cosines into the sum. Having completed these exercises, you will thoroughly master the skill of deriving trigonometric formulas and will not get lost even in the most difficult test, olympiad or testing.